# [算法]动态规划之最长公共子序列

 1 #include<stdio.h>
2 #include<stdlib.h>
3 #include<time.h>
4 #include<string.h>
5
6 #define N 5
7
8 int max(int a, int b, int c) {
9
10     int ab = a>b ? a : b;
11     return ab > c ? ab : c;
12
13 }
14
15 void solve(int *array1, int *array2, int n) {
16     n = n + 1;
17
18     int *pre = (int *)malloc(n * n * sizeof(int));
19     int *dp = (int *)malloc(n * n * sizeof(int));
20     int i;
21     int j;
22     int a, b, c;
23
24     bzero((void *)dp, n * n * sizeof(int));
25     bzero((void *)pre, n * n * sizeof(int));
26
27     for(i = 1; i < n; i++) {
28         for(j = 1; j < n; j++) {
29             a = *(dp + (i -1)*n + j);
30             b = *(dp + i * n + j - 1);
31             c =  *(array1 + j - 1) == *(array2 + i - 1) ? *(dp + (i -1)*n + j - 1) + 1 : *(dp + (i -1)*n + j - 1);
32             *(dp + i * n + j) = max(a, b, c);
33         }
34     }
35
36     for(i = 0; i < n; i++) {
37         for(j = 0; j < n; j++) {
38             printf("%d\t", *(dp + i * n + j));
39         }
40         printf("\n");
41     }
42
43     free(dp);
44     free(pre);
45 }
46
47 int main(char ** args) {
48     srand((unsigned)time(NULL));
49
50     int *array1 = (int *)malloc(N * sizeof(int));
51     for(int i = 0; i < N; i++) {
52         *(array1 + i) = rand() % N;
53         printf("%d\t", *(array1 + i));
54     }
55     printf("\n");
56
57     int *array2 = (int *)malloc(N * sizeof(int));
58     for(int i = 0; i < N; i++) {
59         *(array2 + i) = rand() % N;
60         printf("%d\t", *(array2 + i));
61     }
62
63     printf("\n");
64     printf("\n");
65
66     solve(array1, array2, N);
67
68     free(array1);
69     free(array2);
70     return 0;
71 }

posted @ 2014-12-15 13:52 ~嘉言懿行~~我是煲仔饭~~ 阅读(...) 评论(...) 编辑 收藏