摘要: /*真伤心,学的好慢啊;脑子越来越笨了,根本转不过来;回寝室去啦~~~还需继续努力啊!*///一个长方体 衍生出3个; 对总的进行排序;保证s[i].x>s[i+1].x 如果相等,则保证s[i].y>s[i+1].y;//状态转移方程:dp[i] = max{dp[j]} + s[i].h;#include #include #include #include #include #include #include #define maxn 31 struct stone{ int x; int y; int h; }s[maxn*3]; int dp[m... 阅读全文
posted @ 2013-04-09 22:48 简洁是智慧的灵魂 阅读(128) 评论(0) 推荐(0)
摘要: 状态转移方程:num[p] = min(num[i]*2,num[j]*3,num[k]*5,num[l]*7);#include #include #include #include #include #include #include #define maxn 5900 int num[maxn]; char _th[][11] ={"th","st","nd","rd","th","th","th","th","th&q 阅读全文
posted @ 2013-04-09 18:12 简洁是智慧的灵魂 阅读(151) 评论(0) 推荐(0)