实验四

#include<stdio.h>
long long fun(int n);

int main(){
    int n;
    long long f;

    while(scanf("%d", &n) != EOF){
        f = fun(n);
        printf("n = %d, f = %lld\n", n, f);
    }

    return 0;
}

long long fun(int n){
    if(n == 1)
    return 1;
    else
    return 2*(fun(n-1)+1)-1;
}

　　

实验二

#include<stdio.h>
long long fac(int n);
  
int main(){
    int i, n;
    
    printf("Enter n:");
    scanf("%d", &n);
    
    for(i=1;i<=n;++i)
          printf("%d! = %lld\n", i, fac(i));
        
    return 0;
}
 
long long fac(int n){
    static long long p = 1;
    
    p = p*n;
    
    return p;
}

　　

 

 

#include<stdio.h>
long long fac(int n);

int main(){
    int i, n;

    printf("Enter n:");
    scanf("%d", &n);

    for(i=1;i<=n;++i)
        printf("%d! = %lld\n", i, fac(i));

    return 0;
}

long long fac(int n){
    static long long p = 1;
    printf("p = %lld\n", p);
    p = p*n;
    return p;
}

　　

 

 

 实验三

#include<stdio.h>
#define N 1000

int fun(int n, int m,int bb[N]) {
    int i, j, k=0,flag;
    
    for(j=n;j<=m;j++){
        flag = 1;
        for(i=2;i<j;i++)
        if(j % i == 0){
            flag = 0;
            break;    
        }
        if(flag == 1)
        bb[k++] = j;    
    }
    return k;
}
  
int main(){
    int n=0, m=0, i, k, bb[N];
    
    while(scanf("%d %d",&n, &m) != EOF){
    

    
    for(i=0;i<m-n;i++)
        bb[i] = 0;
        
    k=fun(n,m,bb);
    
    for(i=0;i<k;i++)
        printf("%4d",bb[i]);
        printf("\n");
}
        
    return 0;
}

　　

 

 实验四

#include <stdio.h>
void dec2n(int x, int n);

int main() {
    int x;

    printf("输入一个十进制整数: ");
    scanf("%d", &x);

    dec2n(x, 2);
    dec2n(x, 8);
    dec2n(x,16);
    return 0;
}

void dec2n(int x, int n) {
    int i,a,N;
    char b[100];

    for(i=0;x!=0;i++){
    b[i] = x % n;
    x =  x / n ;
    }
    if(b[i]>9)
    switch(b[i])
    {
        case 10:b[i]='A';break;
        case 11:b[i]='B';break;
        case 12:b[i]='C';break;
        case 13:b[i]='D';break;
        case 14:b[i]='E';break;
        case 15:b[i]='F';break;
    }

    printf("%2d进制：", n);
    for(N=i-1;N>=0;N--)
    printf("%X" ,b[N]);
    printf("\n");

}