杭电acm2097

http://acm.hdu.edu.cn/showproblem.php?pid=2097

解法同1197，输出有些不一样而已

View Code 
 1 #include <stdio.h>
 2 int main()
 3 {
 4     int i, n, sum10, sum12, sum16,a[10000];
 5     for (i=1000; i<10000; i++){
 6         n = i;
 7         sum10 = 0;
 8         while (n){
 9             sum10 += n%10;
10             n /= 10;
11         }
12         n = i;
13         sum12 = 0;
14         while (n){
15             sum12 += n%12;
16             n /= 12;
17         }
18         n = i;
19         sum16 = 0;
20         while (n){
21             sum16 += n%16;
22             n /= 16;
23         }
24         if (sum10==sum12 && sum12==sum16)
25           a[i]=1;
26         else a[i]=0;
27     }
28     while(scanf("%d",&n)&&n)
29       if(a[n])
30         printf("%d is a Sky Number.\n",n);
31       else printf("%d is not a Sky Number.\n",n);
32     return 0;
33 }

 

posted @ 2013-04-09 22:42  执着追求的IT小小鸟  阅读(227)  评论(0)  编辑  收藏  举报