GetNumber的实现(Python & Java & Golang)

TCO2014的编程赢取门票的题目,大致是从一个数组(大小为K),可以选取1~K个数,必须保证这n个数是从1~n,返回所有的选取方法个数。

思路:首先是得到从1开始连续的数,保存每个数的个数。然后通过排列组合得到结果。

当时采用的Python编写,大致的模样是这样(题目要求的类名就略去了):

 

def getNumber(type):
    c = [0] * len(type)
    s = 0
    p = 0
    for x in type:
        if x <= len(type):
            c[x-1] += 1
    for i in c:
        if i == 0:
            return s
        else:
            if s == 0:
                s = i
                p = i
            else:
                p *= i
                s += p
    return s

print getNumber([2])
print getNumber([1, 2])
print getNumber([1, 3, 2])
print getNumber([1, 1, 2])
print getNumber([1, 3, 2, 5, 7, 4, 5, 4])
print getNumber([1, 1, 2, 2, 3, 3, 4, 4, 5, 5])

 

之后尝试了一下 Java 版本:

package org.huys.algo.problem;

public class WinterAndCandies {

    public static int getNumber(int[] type) {
        int[] c = new int[type.length];
        int s = 0;
        int p = 0;

        for (int i=0; i<type.length; i++) {
            if (type[i] <= type.length) {
                c[type[i]-1] += 1;
            }
        }

        for (int i=0; i<c.length; i++) {
            if (c[i] == 0) {
                return s;
            } else {
                if (s == 0) {
                    s = c[i];
                    p = c[i];
                } else {
                    p *= c[i];
                    s += p;
                }
            }
        }
        return s;
    }

    public static void main(String[] args) {
        System.out.println(getNumber(new int[] {2}));
        System.out.println(getNumber(new int[] {1, 2}));
        System.out.println(getNumber(new int[] {1, 3, 2}));
        System.out.println(getNumber(new int[] {1, 1, 2}));
        System.out.println(getNumber(new int[] {1, 3, 2, 5, 7, 4, 5, 4}));
        System.out.println(getNumber(new int[] {1, 1, 2, 2, 3, 3, 4, 4, 5, 5}));
    }
}

 最近开始关注golang和swift,两种语言有很多共通之处。golang没有class,还是不免有些不适。

package main

import "fmt"

func getNumber(types []int) int {
	var s = 0
	var p = 0
	var c = make([]int, len(types))

	for _, value := range types {
		if value <= len(types) {
			c[value-1] += 1
		}
	}

	for _, i := range c {
		if i == 0 {
			return s
		} else {
			if s == 0 {
				s = i
				p = i
			} else {
				p *= i
				s += p
			}
		}
	}
	return s
}

func main() {
    fmt.Println(getNumber([]int {2}))
    fmt.Println(getNumber([]int {1, 2}))
    fmt.Println(getNumber([]int {1, 3, 2}))
    fmt.Println(getNumber([]int {1, 1, 2}))
    fmt.Println(getNumber([]int {1, 3, 2, 5, 7, 4, 5, 4}))
    fmt.Println(getNumber([]int {1, 1, 2, 2, 3, 3, 4, 4, 5, 5}))
}

 代码中主要是数组相关操作。相对而言,Python 最灵活。Golang 中采用 Slice 语法,与同为C系语言的Java颇为接近。

 

posted @ 2014-08-25 23:50  独木  阅读(2344)  评论(0编辑  收藏  举报