代码随想录：最佳买卖股票时机含冷冻期

class Solution {
public:
    int maxProfit(vector<int>& prices) {
        vector<vector<int>>dp = vector<vector<int>>(prices.size(),vector<int>(3,0));
        //0持有，1冷冻期，2不持有
        dp[0][0] = -prices[0];
        dp[0][1] = 0;
        dp[0][2] = 0;

        for(int i = 1;i<prices.size();i++){
            dp[i][0] = max(dp[i-1][0],dp[i-1][2]-prices[i]);
            dp[i][1] = dp[i-1][0]+prices[i];
            dp[i][2] = max(dp[i-1][2],dp[i-1][1]);
        }
        return max(dp[prices.size()-1][1],dp[prices.size()-1][2]);
    }
};