摘要: #include int main(void) { int n,i,j,a,b,c,d; int a[4][4]; scanf("%d %d %d",&n,&i,&j); a=0; b=0; for(i=1;i<=4;i++){ a=a+1; b=b+1; printf("(i,%d)",a); printf("(%d,j)",b); } for(i=1;i<=4;i++) for(j=1;j<=4;j++) i=i-1; 阅读全文
posted @ 2013-12-09 09:46 huangsilinlana 阅读(119) 评论(0) 推荐(0)
摘要: #includeint main(void){ int m,n,i; double h,s; scanf("%d %d",&m,&n); s=0; for(i=1;i<=n;i++){ s=s+m; m=m/2; s=s+m; } h=m; printf("%.2f %.2f",h,s); return 0;} 阅读全文
posted @ 2013-12-09 09:32 huangsilinlana 阅读(78) 评论(0) 推荐(0)
摘要: #includeint main(void){ int count,number; int a,b,c,d,e; count=0; scanf("%d",&number); do{ number=number/10; count++; }while(number!=0); if(count=1){ a=number; printf("%d\n",count); printf("%d",a); } else if(count=2){ a=number/10; b=number-a*10; printf("%d\n&qu 阅读全文
posted @ 2013-12-09 09:03 huangsilinlana 阅读(102) 评论(0) 推荐(0)