摘要: #includeint main(void){ double x,y; printf("Enter x:"); scanf("%lf",&x); if(x<0){ y=-1; } else if(x=0){ y=0; } else{ y=1; } printf("sign(x)=%.2f\n",y); return 0;} 阅读全文
posted @ 2013-10-19 23:46 huangsilinlana 阅读(191) 评论(0) 推荐(0)
摘要: int main(void){ int i,n; double e; printf("Enter n:"); scanf("%d",&n); for(i=1;i<=n;i++){ e=fact(i); printf("e=%.2f\n",e); } return 0;}double fact(int n){ int i; double product; product=1; for(i=1;i<=n;i++){ product=product*i; } return product;} 阅读全文
posted @ 2013-10-19 23:22 huangsilinlana 阅读(92) 评论(0) 推荐(0)
摘要: #include#includeint main(void){ int loan,month; double rate,money; printf("Enter loan:"); scanf("%d",&loan); printf("Enter month:"); scanf("%d",&month); printf("Enter rate:"); scanf("%lf",&rate); money=loan*rate*pow(1+rate,month 阅读全文
posted @ 2013-10-19 23:03 huangsilinlana 阅读(92) 评论(0) 推荐(0)
摘要: #include#includeint main(void){ int n,i,sum; printf("Enter n:"); scanf("%d",&n); sum=0; for(i=1;i<=n;i++){ sum=pow(2,i); } printf("sum=%.d\n",sum); return 0;} 阅读全文
posted @ 2013-10-19 22:47 huangsilinlana 阅读(96) 评论(1) 推荐(0)
摘要: #includeint main(void){ int denominator,i,n; double item,sum,flag; flag=1; denominator=1; sum=0; printf("Enter n:"); scanf("%d",&n); for(i=1;i<=n;i++){ item=(flag*i)/denominator; sum=sum+item; flag=-flag; denominator=denominator+2; } printf("sum=%.2f\n",sum); ret 阅读全文
posted @ 2013-10-19 22:39 huangsilinlana 阅读(105) 评论(1) 推荐(0)
摘要: #includeint main(void){ int denominator,n,i; double sum,m; printf("Enter n:"); scanf("%d",&n); sum=0; denominator=1; for(i=m;i<=n;i++){ sum=sum+i*i+1.0/denominator; denominator=denominator+1; } printf("sum=%.2f\n",sum); return 0;} 阅读全文
posted @ 2013-10-19 22:03 huangsilinlana 阅读(177) 评论(1) 推荐(0)
摘要: #include int main() { double x,pow = 1.0; int i,n; printf("Enter x:"); scanf("%lf",&x);printf("Enter n:");scanf("%d",&n); for(i=1;i<=n;i++){pow=pow*x;}printf("pow(%lf%d)=%.2f\n",x,n,pow);return 0;} 阅读全文
posted @ 2013-10-19 21:36 huangsilinlana 阅读(86) 评论(1) 推荐(0)
摘要: #includeint main(void){ int i,m; double e,s; double cylinder(double e); printf("Enter m:\n"); scanf("%d",&m); for(i=1;i50){ result=0.58*(e-50)+26.5; } else{ result=0.53*e; } return result;} 阅读全文
posted @ 2013-10-19 21:11 huangsilinlana 阅读(99) 评论(0) 推荐(0)
摘要: /*输入电量e,求电费*/#includeint main(void){ double e,s; /*定义两个双精度浮点型变量*/ printf("Enter e:\n"); /*输入提示*/ scanf("%lf",&e); /*调用scanf()函数输入数据*/ if(e50){ s=26.5+0.58*(e-50); } else{ s=0.53*e; } printf("s=%.2f\n",s); /*调用pr... 阅读全文
posted @ 2013-10-19 20:50 huangsilinlana 阅读(106) 评论(1) 推荐(0)
摘要: /*求解简单的五则运算表达式*/#includeint main(void){ double num1,num2; char op; printf("Type in an expression:"); /*提示输入一个表达式*/ scanf("%lf%c%lf",&num1,&op,&num2); /*输入表达式*/ if(op=='+') /*判断运算符是否为’+‘*/ printf("=%.2f\n",num1+num2); else if(op=='-') /*判断运算符是 阅读全文
posted @ 2013-10-19 20:34 huangsilinlana 阅读(156) 评论(1) 推荐(0)