摘要: with open('data3.txt','r+', encoding='UTF-8') as f: num = [line.strip('\n') for line in f] num.pop(0) num_print = [eval(i) for i in num] print(f"原始数据: 阅读全文
posted @ 2022-05-16 23:14 10309 阅读(26) 评论(2) 推荐(0) 编辑