代码改变世界

Least Common Multiple

2016-02-28 14:15 by 想打架的蜜蜂, 157 阅读, 0 推荐, 收藏,
摘要：Least Common Multiple Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 43071 Accepted Submission(s 阅读全文

Big Number

2016-02-28 10:31 by 想打架的蜜蜂, 224 阅读, 0 推荐, 收藏,
摘要：Big Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 32913 Accepted Submission(s): 15481 Pr 阅读全文

A Mathematical Curiosity

2016-02-28 10:07 by 想打架的蜜蜂, 407 阅读, 0 推荐, 收藏,
摘要：A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 34939 Accepted Submissio 阅读全文

Uniform Generator

2016-02-27 21:48 by 想打架的蜜蜂, 376 阅读, 0 推荐, 收藏,
摘要：Uniform Generator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23843 Accepted Submission(s): 9 阅读全文

Digital Roots

2016-02-27 20:57 by 想打架的蜜蜂, 336 阅读, 0 推荐, 收藏,
摘要：Digital Roots Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 65092 Accepted Submission(s): 20292 阅读全文

u Calculate e

2016-02-26 22:16 by 想打架的蜜蜂, 333 阅读, 0 推荐, 收藏,
摘要：u Calculate e Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 39381 Accepted Submission(s): 17893 阅读全文

Elevator

2016-02-26 21:30 by 想打架的蜜蜂, 241 阅读, 0 推荐, 收藏,
摘要：Elevator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 59259 Accepted Submission(s): 32539 Prob 阅读全文

Number Sequence

2016-02-26 14:56 by 想打架的蜜蜂, 207 阅读, 0 推荐, 收藏,
摘要：Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 142553 Accepted Submission(s): 34 阅读全文

Max Sum

2016-02-26 10:17 by 想打架的蜜蜂, 150 阅读, 0 推荐, 收藏,
摘要：先看看题目要求： Max Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 26441 Accepted Submission(s): 55 阅读全文

assert()函数用法总结

2015-11-15 13:16 by 想打架的蜜蜂, 190 阅读, 0 推荐, 收藏,
摘要：assert()函数用法总结 assert宏的原型定义在中，其作用是如果它的条件返回错误，则终止程序执行，原型定义：#include void assert( int expression ); assert的作用是现计算表达式 expression ，如果其值为假（即为0），那么它先向stde... 阅读全文