摘要:
<?php $filename="./img/img01.jpg"; $img=imagecreatefromjpeg($filename); header("Content-Type:image/jpeg"); imagejpeg($img); imagejpeg($img,"./img/copy 阅读全文
posted @ 2022-08-12 23:09
paoPaoLong_liu
阅读(255)
评论(0)
推荐(0)

浙公网安备 33010602011771号