摘要: <?php $filename="./img/img01.jpg"; $img=imagecreatefromjpeg($filename); header("Content-Type:image/jpeg"); imagejpeg($img); imagejpeg($img,"./img/copy 阅读全文
posted @ 2022-08-12 23:09 paoPaoLong_liu 阅读(255) 评论(0) 推荐(0)