摘要: 按CategoryID分组并排序,Names为相同的CategoryID的PropertyXngName以‘,’连接select t.CategoryID,Names = stuff((select ',' +c.PropertyXngName from [develop].[dbo].[Xng_Properties] c where t.CategoryID = c.CategoryID for XML path('')) , 1 , 1 , '') from [develop].[dbo].[Xng_Properties] t Group b 阅读全文
posted @ 2011-04-08 13:05 如歌 阅读(216) 评论(0) 推荐(0)