实验作业2

实验1:

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#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define N 5 
#define N1 80
#define N2 35

int main ()
{
	int cnt;
	int random_major, random_no;
	srand(time(NULL));
	
	cnt = 0;
	while(cnt < N)
	{
		random_major = rand()%2;
		if(random_major)
		{
			random_no = rand ()%N1 +1;
			printf("20256343%04d \n", random_no);
		}
		else
		{
			random_no = rand()%N2 +1;
			printf("20256136%04d\n",random_no);
		}
		cnt++;
		
	} 
	return 0;
}
Q1:srand(time(NULL))的作用是随机生成,并且随着时间而改变。若去掉后,第一次的随机数据就会成为后面每一次的结果。 Q2:随机生成5个学号开头为20256343和20256136。 实验2:
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#include <stdio.h>
 
int main()
{
	int choice, quantity;
	float total_price = 0, amount_paid, change;
	
	while (1)
	{
		printf("\n自动饮料售卖机菜单:\n");
		printf("1.可乐 - 3元/瓶 \n"); 
		printf("2.雪碧 - 3元/瓶 \n");
		printf("3.橙汁 - 3元/瓶 \n");
		printf("4.款泉水 - 3元/瓶 \n");
		printf("0.退出购买流程 \n");
		printf("请输入饮料编号:");
		scanf("%d", &choice);
		
		if (choice == 0)
		break;
		
		if (choice <1 || choice >4)
		{
			printf("无效的饮料编号,请重新输入。\n");
			continue;
		}
		
		printf("请输入购买的数量:");
		scanf("%d", &quantity);
		
		if (quantity < 0)
		{
		    printf("购买数量不能为负数,请重新输入。\n");
		    continue;
		}
		if (choice == 1 || choice == 2)
		    total_price += 3 * quantity;
		else if(choice == 3)
		    total_price += 5 * quantity;
		else
		    total_price += 2 * quantity;
		
		printf("请输入金额:");
		scanf("%f",&amount_paid);
		
		change = amount_paid - total_price;
		printf("本次购买总价: %.2f 元\n", total_price);
		printf("找零:%.2f 元\n",change);
		
		total_price = 0; 
	} 
	printf("感谢您的购买,欢迎下次光临");
	return 0; 
}
Q1:避免在第二次往后的与运行中total_price的初始值不为0。 Q2:触发continue语句时结束当前循环,不在运行下面还没开始运行的语句,且直接回到当前循环最前面。

实验3:

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#include <stdio.h>
int main ()
{
	char ans;
	while(scanf("%c",&ans)!= EOF)
	{
		if(ans == 'y')
		printf("wait a minute\n");
		else if (ans == 'g')
		printf("go go go\n");
		else if(ans == 'r')
		printf("stop!\n");
		else if("ans == '\n'")
		continue; 
		else
		printf("something must be wrong...\n");
		
	}
	return 0;
} 

屏幕截图 2025-10-15 191936
实验4:

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#include <stdio.h>
int main ()
{
	float cost,total,max,min;
	max = 0.0;
	min = 20000.0;
	total = 0.0;
	printf("输入今日开销,直到输入-1终止:\n"); 
	while(1)
	{
		scanf("%f",&cost);
		if(cost == -1)
		break;
		else 
		{
			if(cost > max)
		    max = cost;
		    if(min > cost)
		    min = cost;
		    if(cost > 0 && cost <= 20000)
		    total += cost;
		    else
		    break;
		}		 	
	} 
	printf("今日累计消费总额:%.1f,\n",total);
	printf("今日最高一笔开销:%.1f,\n",max);
	printf("今日最低一笔开销:%.1f,\n",min);
	return 0;
} 

屏幕截图 2025-10-15 195256
实验5:

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#include <stdio.h>
int main ()
{
	int a,b,c;
	while(scanf("%d%d%d",&a,&b,&c)!= EOF)
	{
		if(a + b > c && b + c > a && a + c > b)
		{
			if((a == b || b == c|| a == c ) && ( a != b|| a !=c|| b !=c ))
			printf("等腰三角形\n");
			else if(a == b && b == c && a == c)
			printf("等边三角形\n");
			else if((a*a == b*b +c*c) || (b*b == c*c + a*a) || (c*c == b*b + a*a))
			printf("直角三角形\n");
			else
			printf("普通三角形\n");
		}
		else
		printf("不能构成三角形\n"); 
	}
	 
	return 0;
} 

屏幕截图 2025-10-15 203201
实验6:

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#include <stdio.h>
#include <time.h> 
#include <stdlib.h> 
int main ()
{
	int i, ans;
	srand(time(NULL));
	
    int a = rand () %30 + 1 ;
	printf("猜猜2025年11月哪天是你的Lucky day\n");
	printf("开始喽,你有三次机会,猜吧(1~30):\n");
	for(i = 0;i < 3;i++) 
	{
		scanf("%d",&ans);
		if(ans > a)
		{
			printf("你猜的日期晚了,你的Lucky day还在前面哦\n");
			continue;
		}
	    else if(ans < a)
	    {
	    	printf("你猜的日期早了,你的Lucky day还没到呢\n");
	    	continue;
		}
		else
		{
			printf("哇,猜中了\n");
			break;
		} 
	}
	if(i == 3) 
	printf("次数用光了。偷偷告诉你,11月你的Lucky day是%d\n",a);
	return 0;
} 

屏幕截图 2025-10-15 211611

posted @ 2025-10-16 19:44  hhqdream  阅读(1)  评论(0)    收藏  举报