对现有REST API更新为GraphQL API [升级版]

前序

https://zhuanlan.zhihu.com/p/113911857

背景

        老板让可以控制最小子序列的输入输出

不变内容

框架及语言
GraphQL API需求
需要新增安装的模块
基本知识
原始单条数据返回结构
测试方法

解决办法

import collections
from graphene import ObjectType, String, Schema, Int, List, Field
import json


class Clsseven(ObjectType):
    xxx = String()
    xxxxx = String()


class Image(ObjectType):
    large_image = String()
    medium_image = String()
    small_image = String()
    swatch_image = String()

class PersonType(ObjectType):
    one = List(String)
    two = String()
    image = Field(Image)
    four = String()
    id = String()
    six = String()
    seven = Field(Clsseven)


def _json_object_hook(d):
    return collections.namedtuple('X', d.keys())(*d.values())


def json2obj(data):
    return json.loads(data, object_hook=_json_object_hook)


class Query(ObjectType):
    """
    GraphQL API 方法有 search
    输入参数为 id count 
    """
    search = List(PersonType, id=String(), count=Int(default_value=5), description="Get search details")

    def resolve_search(root, info, id, count):
        data = 原始获取数据方式(id)
        response = json2obj(json.dumps(data))
        return response[:count]

schema = Schema(query=Query)

app.add_url_rule('/graphql', view_func=GraphQLView.as_view('graphql', schema=schema, graphiql=True, pretty=True))

if __name__ == '__main__':
    app.run()

请求结构

浏览器直接请求测试结构

{
  search(id: "lslsl", count:3) {
    one
    two
    id
    image{
        large_image
        small_image
    }
    seven{
        xxx
    }
  }
}