Herumw - 博客园

摘要： Problem DescriptionA hat’s word is a word in the dictionary that is the concatenation of exactly two other words in the dictionary.You... 阅读全文

posted @ 2016-02-05 13:37 Herumw 阅读(119) 评论(0) 推荐(0) 编辑

摘要： Problem DescriptionGiven a list of phone numbers, determine if it is consistent in the sense that no number is the prefix of another. ... 阅读全文

posted @ 2016-02-05 12:11 Herumw 阅读(153) 评论(0) 推荐(0) 编辑

摘要： Genos recently installed the game Zuma on his phone. In Zuma there exists a line of n gemstones, the i-th of which has color ci. The g... 阅读全文

posted @ 2016-02-05 08:15 Herumw 阅读(153) 评论(0) 推荐(0) 编辑

摘要： DescriptionMato同学从各路神犇以各种方式（你们懂的）收集了许多资料，这些资料一共有n份，每份有一个大小和一个编号。为了防止他人偷拷，这些资料都是加密过的，只能用Mato自己写的程序才能访问。Mato每天随机选一个区间[l,r]，他今天就看编号在此区间内的... 阅读全文

posted @ 2016-02-04 20:23 Herumw 阅读(100) 评论(0) 推荐(0) 编辑

摘要： An array of positive integers a1, a2, ..., an is given. Let us consider its arbitrary subarray al, al + 1..., ar, where 1 ≤ l ≤ r ≤ n.... 阅读全文

posted @ 2016-02-04 18:25 Herumw 阅读(102) 评论(0) 推荐(0) 编辑

摘要： time limit per test4 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputBob has a favorite number k and ... 阅读全文

posted @ 2016-02-04 15:00 Herumw 阅读(112) 评论(0) 推荐(0) 编辑

摘要： Time Limit: 20 Sec Memory Limit: 259 MBSubmit: 5307 Solved: 2450[Submit][Status][Discuss]Description作为一个生活散漫的人，小Z每天早上都要耗费很久从一堆五颜六色的袜... 阅读全文

posted @ 2016-02-04 12:44 Herumw 阅读(123) 评论(0) 推荐(0) 编辑

摘要： Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131070/65535 K (Java/Others)Total Submission(s): 27751 Accepted Submission(... 阅读全文

posted @ 2016-02-03 21:39 Herumw 阅读(99) 评论(0) 推荐(0) 编辑

摘要： There are b blocks of digits. Each one consisting of the same n digits, which are given to you in the input. Wet Shark must chooseexac... 阅读全文

posted @ 2016-02-03 09:52 Herumw 阅读(136) 评论(0) 推荐(0) 编辑

摘要： Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 77 Accepted: 10Description随着YYHS的OI集训队人数急剧增加，原有的小机房已经容纳不了数量庞大的队员。于是史老师决定租用一些... 阅读全文

posted @ 2016-01-27 20:06 Herumw 阅读(128) 评论(0) 推荐(0) 编辑

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