摘要:
查询两个表中不同的数据select ecs_brand.brand_id,ecs_brand.brand_name from 表名ecs_brand where ecs_brand.brand_id not in (select distinct ecs_goods.brand_id from 表名 阅读全文
摘要:
var all = 21; var people = [0,0,0,0,0]; for(var i=1;i0){ people[start]++; all--; start--; if (start<=0) {start = people.length-1}; } alert(people[people.length-1]) 阅读全文