摘要: int n, i, sum1 = 0, sum2 = 0, sum3 = 0, m, ave1,ave2,ave3,max = 0; cin>>n; for(int i = 1;i <= n;i++) { scanf("%c",&a[i]); scanf(" %s",b[i]); scanf("%d 阅读全文
posted @ 2018-11-18 10:21 几欢 阅读(80) 评论(0) 推荐(0)