## 实验4 函数与异常处理应用编辑

print(sum)
sum = 42
print(sum)

def inc(n):
sum = n+1
print(sum)
return sum

sum = inc(7) + inc(7)
print(sum)

1.sum函数未创建，内建函数作用域中不能改变

2.sum被赋予全局变量42

3.sum被赋予局部变量n+1

4.sum被inc（7）+inc（7）改变

def func1(a, b, c, d, e, f):
'''
返回参数a,b,c,d,e,f构成的列表
默认，参数按位置传递; 也支持关键字传递
'''
return [a,b,c,d,e,f]

def func2(a, b, c,*, d, e, f):
'''
返回参数a,b,c,d,e,f构成的列表
*后面的参数只能按关键字传递'''
return [a,b,c,d,e,f]

def func3(a, b, c, /, d, e, f):
'''
返回参数a,b,c,d,e,f构成的列表
/前面的参数只能按位置传递'''
return [a,b,c,d,e,f]

#func1调用：按位置传递、按参数传递都可以
print( func1(1,9,2,0,5,3) )
print( func1(a=1, b=9, c=2, d=0, e=5, f=3) )
print( func1(1,9,2, f=3, d=0, e=5))

#func2调用：d,e,f必须按关键字传递
print( func2(11, 99, 22, d=0, e=55, f=33) )
print( func2(a=11, b=99, c=22, d=0, e=55, f=33) )

#func3调用：a,b,c必须按位置传递
print( func3(111, 999, 222, 0, 555, 333))
print( func3(111, 999, 222, d=0, e=555, f=333))

line33后加一行函数调用

print( func2(11, 99, 22, 0, 55, 33))

line38后加一行函数调用

print(func3(a=111, b=999, c=222, 0, 555, 333) )

list1 = [1,9,8,4]

print(sorted(list1))
print(sorted(list1,reverse=True))
print(sorted(list1,True))

def func(a,b,c,/,*,d,e,f):
return([a,b,c,d,e,f])

print(func(1,2,3,d=4,e=5,f=6))

def solve(a, b, c):
'''
求解一元二次方程, 返回方程的两个根
:para: a,b,c: int 方程系数
:return: tuple '''
delta = b*b - 4*a*c
delta_sqrt = abs(delta)**0.5
p1 = -b/2/a;
p2 = delta_sqrt/2/a
if delta>=0:
root1 = p1 + p2
root2 = p1 - p2
else:
root1 = complex(p1, p2)
root2 = complex(p1, -p2)

return root1, root2

while True:
try:
a,b,c = eval(input('Enter eqution coefficient: '))
if a == 0:
raise
except:
print('invalid input, or, a is zero')
break
else:
root1, root2 = solve(a, b, c)
print(f'root1 = {root1:.2f}, root2 = {root2:.2f}')
print()

line22前加入一行代码：

print(solve.__doc__)

def list_generator(x,y,z=1):
list_1=[]
while x<=y:
list_1.append(x)
x+=z
return list_1

list1=list_generator(-5,5)
print(list1)

list2=list_generator(-5,5,2)
print(list2)

list3=list_generator(1,5,0.5)
print(list3)

def is_prime(n):
if n == 1:
return False
elif n == 2:
return True
else:
for i in range(2,n):
if n%i == 0:
return False
return True

k = 0
for i in range(2,21,2):
for j in range(1,i):
m = i-j
if is_prime(m) and is_prime(j) and j<=m:
print(i,'=',j,'+',m,)
k += 1
if k%6==0:
print('\n')

x=str(input('输入英文文本：'))
z=0
for i in range(len(x)):
if 128>ord(x[i])+5>122 or 96>ord(x[i])+5>90:
a=ord(x[i])-21
z=z+1
elif 65<=ord(x[i])<=85 or 97<=ord(x[i])+5<=117:
a=ord(x[i])+5
z=z+1
else:
a=ord(x[i])
z=z+1
if z==1:
print('编码后的文本',end='')
print(chr(a),end='')
print()
print('对编码后的文本解码',x)

def collatz(n):
l=[n]
while l[-1] != 1:
if l[-1] % 2 == 0 :
l.append((l[-1])//2)
else:
l.append((l[-1])*3+1)
return l

try:
x=int(input('enter a positive integer:'))
if x <= 0:
raise
except:
print('Error: must be a positive integer')
else:
print(collatz(x))

 

posted on 2022-05-09 23:47  haze13327620097  阅读(12)  评论(4编辑  收藏  举报