实验五

task3:

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with open('data3.txt','r+', encoding='UTF-8') as f:
    x = [line.strip('\n') for line in f]
    x.pop(0)
    x_print = [eval(i) for i in x]
    print(f"原始数据:\n{x_print}")
    x_new = [round(eval(i)) for i in x]
    print(f'四舍五入后的数据:\n{x_new}')

with open('data3_processed.txt','w') as f:
    write1 = ['原始数据'] + [str(i) for i in x]
    write2 = ['四舍五入后的数据'] + [str(i) for i in x_new]
    for i in range(len(x)):
        f.write(f"{write1[i]}\t{write2[i]}\n")
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 task4:

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with open('data4.txt','r+',encoding='utf-8') as f:
    str=[i.strip('\n').split('\t') for i in f]
    a=str.pop(0)
    str.sort(key=lambda x : (x[2],-int(x[-1])))
    print('\t'.join(a))
    for i in str:
        print('\t'.join(i))
with open('data4_progressed.txt','w') as f:
    f.write('\t'.join(a))
    f.write('\n')
    for i in str:
        f.write('\t'.join(i))
        f.write('\n')
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 task5:

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with open('data5.txt', 'r+', encoding='UTF-8') as f:
    text = ''.join([i for i in f])
    print(f'行数:{len(text.splitlines())}')
    print(f'单词数:{len(text.split())}')
    print(f"空格数:{text.count(' ')}")
    print(f'字符数:{len(text)}')

with open('data5_with_line.txt', 'w', encoding='UTF-8') as f:
    for i in range(len(text.splitlines())):
        f.write('{} {}'.format(i+1,text.split('\n')[i]))
        f.write('\n')
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posted @ 2022-05-17 19:14  MeiKoY  阅读(7)  评论(2编辑  收藏  举报