04 2021 档案

摘要:def max_num_compare(n1, n2): if n1 > n2: return n1 else: return n2 def max_num(n1, n2, n3): m = max_num_compare(n1, n2) if m > n3: return m else: retu 阅读全文
posted @ 2021-04-15 15:47 mbcwdl 阅读(1112) 评论(0) 推荐(0)