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思路不难,但是细节还是挺多的,要格外注意一下. code: #include <cstdio> #include <queue> #include <cstring> #include <algorithm> #define N 2005 #define ll long long #define m 阅读全文
posted @ 2019-12-23 20:43
EM-LGH
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code: #include <cstdio> #include <cstring> #include <algorithm> #define N 100020 #define ll long long #define setIO(s) freopen(s".in","r",stdin) using 阅读全文
posted @ 2019-12-23 18:49
EM-LGH
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code: #include <cstdio> #include <algorithm> #define N 50020 #define ll long long #define setIO(s) freopen(s".in","r",stdin) using namespace std; stru 阅读全文
posted @ 2019-12-23 16:44
EM-LGH
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你发现平均值不会很大,所以直接暴力枚举平均值,然后跑 4*100 次最小生成树取最小值即可. code: #include <cstdio> #include <cmath> #include <algorithm> #define N 2005 #define ll long long #defi 阅读全文
posted @ 2019-12-23 16:28
EM-LGH
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非常好的一道思维题. code: #include <cstdio> #include <cstring> #include <algorithm> #include <vector> #define lson x<<1 #define rson x<<1|1 #define N 500010 #d 阅读全文
posted @ 2019-12-23 15:43
EM-LGH
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