摘要: task4 #include <stdio.h> #include <stdlib.h> int main(){ int i=0; FILE *fp; char ch; fp=fopen("data4.txt","r"); if(fp==NULL){ printf("fail to open\n") 阅读全文
posted @ 2023-06-09 15:16 赵正 阅读(22) 评论(0) 推荐(0)