AlgebraMaster

摘要：1,cubic-bezier vector start = point(0,"P",0); vector end = point(0,"P",@numpt-1); vector range_01 = fit(@ptnum,0,@numpt-1,0,1); float ix = range_01.x; 阅读全文

摘要：1,曲线y = sqrt(x) 和 点(3/2,0) 最近距离为多少 设最近点为(x,y) 则D = d^2 = (x-3/2)^2 + (y-0)^2 所以D = (x-3/2)^2 + [sqrt(x)-0]^2 因为y = sqrt(x) 所以D = (x-3/2)^2 + x = x^2 - 阅读全文

摘要：1,先花个圆: detail模式执行。 #define XY 0x00 #define XZ 0x01 #define YZ 0x02 #define pi 3.1415926 #define close 0x01 #define unclose 0x00 vector center = {1,0, 阅读全文