描述:简单题 问题描述 给定n个整数表示一个商店连续n天的销售量。如果某天之前销售量在增长,而后一天销售量减少,则称这一天为折点,反过来如果之前销售量减少而后一天销售量增长,也称这一天为折点。其他的天都不是折点。如下图中,第3天和第6天是折点。 给定n个整数a1, a2, …, an表示销售量,请计 Read More
posted @ 2016-08-06 20:08 A-inspire Views(1469) Comments(0) Diggs(0)
这道题目非常简单! 问题描述 有 N 个非零且各不相同的整数。请你编一个程序求出它们中有多少对相反数(a 和 -a 为一对相反数)。 输入格式 第一行包含一个正整数 N。(1 ≤ N ≤ 500)。 第二行为 N 个用单个空格隔开的非零整数,每个数的绝对值不超过1000,保证这些整数各不相同。 输出 Read More
posted @ 2016-08-06 19:39 A-inspire Views(652) Comments(0) Diggs(0)
#include<iostream>#include<algorithm>using namespace std;struct node //定义结构体{ int num;//数据 int count;//出现的次数 计数};bool cmp(node a, node b)//排序{ if (a.c Read More
posted @ 2016-08-06 19:26 A-inspire Views(1182) Comments(0) Diggs(0)
#include <stdio.h> #define MAXN 64 int a[MAXN + 1][MAXN + 1] = { 0 }; void gamecal(int k, int n)//处理编号k开始的n个选手的日程 { int i, j; if (n == 2) { a[k][1] = Read More
posted @ 2016-08-06 14:43 A-inspire Views(185) Comments(0) Diggs(0)
#include <stdio.h>#include <windows.h>#include<string.h>int main() { int oldprice, price = 0, i = 0; printf("请首先设置商品的真实价格:"); scanf("%d", &oldprice); Read More
posted @ 2016-08-06 01:21 A-inspire Views(259) Comments(0) Diggs(0)
#include<stdio.h>int main(){ int num1, num2,temp; scanf("%d%d",&num1,&num2); int t1 = num1; int t2 = num2; while (num2 != 0) { temp = num1%num2; num1 Read More
posted @ 2016-08-03 19:06 A-inspire Views(230) Comments(0) Diggs(0)
#include<stdio.h>int main(){ int one,tow,five,num=1; for (one = 1; one < num*10; one++) { for (tow = 1; tow < num*10 / 2; tow++) { for (five = 1; five Read More
posted @ 2016-08-03 18:50 A-inspire Views(1642) Comments(0) Diggs(0)
#include<stdio.h>#include<stdlib.h>#include<time.h>int main(){ int i; for(i=1;i<=5;i++) { printf("i=%d\n",i); }printf("i最后的值为%d\n",i);return 0;}/* for Read More
posted @ 2016-08-02 17:47 A-inspire Views(144) Comments(0) Diggs(0)
#include<stdio.h>#include<stdlib.h>#include<time.h>int main(){ int num,i,result=1; scanf("%d",&num); for(i=1;i<=num;i++) { result=result*i; } printf(" Read More
posted @ 2016-08-02 17:33 A-inspire Views(257) Comments(0) Diggs(0)
#include<stdio.h>#include<stdlib.h>#include<time.h>int main(){ srand(time(0)); int ich;int num; do { getchar(); num=rand()%100+1; if(num%6==0) { print Read More
posted @ 2016-08-02 17:14 A-inspire Views(244) Comments(0) Diggs(0)