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int xorOperation(int n, int start){ int val = 0; for (int i=0; i<n; i++) { val ^= start + 2*i; } return val; } 阅读全文
posted @ 2020-08-16 01:12
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int minCount(int* coins, int coinsSize){ int count = 0; for (int i=0; i<coinsSize; i++) { count += coins[i]/2 + coins[i]%2; } return count; } 阅读全文
posted @ 2020-08-15 18:29
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int qusort(int* s,int start,int end) //自定义函数 qusort() { int i,j; //定义变量为基本整型 i= start; //将每组首个元素赋给i j = end; //将每组末尾元素赋给j int k=s[start]; //设置基准值 whil 阅读全文
posted @ 2020-08-15 18:18
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void rotate(int* nums, int numsSize, int k){ k %= numsSize; if (numsSize !=1 && k!=0) { int index = numsSize - k; int* p = (int*)malloc(numsSize*sizeo 阅读全文
posted @ 2020-08-14 19:26
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//异或满足交换律和结合律 int singleNumber(int* nums, int numsSize){ int result = 0; for (int i=0; i<numsSize; i++) result ^= nums[i]; return result; } 阅读全文
posted @ 2020-08-14 16:16
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int mySqrt(int x){ unsigned int i = 0; while(i * i < x) i++; if (i * i == x) return i; return --i; } 阅读全文
posted @ 2020-08-14 14:53
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int getSum(int a, int b){ while(a & b) { unsigned int val_and = a & b; //int val_and = a & b; int val_xor = a ^ b; val_and <<= 1; a = val_and; b = val 阅读全文
posted @ 2020-08-14 13:56
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/** * Definition for a binary tree node. * struct TreeNode { * int val; * struct TreeNode *left; * struct TreeNode *right; * }; */ bool IsSym(struct T 阅读全文
posted @ 2020-08-14 11:18
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bool isPalindrome(int x){ if (x < 0) return false; int num = x; int arr[10] = {0}; int index = 0; while(num!=0) { arr[index] = num % 10; num /= 10; in 阅读全文
posted @ 2020-08-13 18:45
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/** * Note: The returned array must be malloced, assume caller calls free(). */ int* twoSum(int* nums, int numsSize, int target, int* returnSize){ //i 阅读全文
posted @ 2020-08-13 18:23
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