摘要:
View Code SELECT jobTitle FROM job_jobwherecharindex('程序员',jobTitle)>0SELECT jobTitle FROM job_jobwhere jobTitle like'程序员%'select jobTitle from job_jobwherePATINDEX('%程序员%',jobTitle)>0select jobTitle from job_jobwherecontains(jobTitle,'程序员')select jobTitle from 阅读全文
posted @ 2011-07-21 14:00
freexiaoyu
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