摘要: HDU 1176 免费馅饼其实就是数塔问题,由后往前推!code:#include <iostream>using namespace std;int max(int a,int b,int c){ int temp = a; if(temp < b) temp = b; if(temp < c) temp = c; return temp;}int dp[100004... 阅读全文
posted @ 2010-02-27 20:48 forward power 阅读(205) 评论(0) 推荐(0) 编辑