饭后温柔

摘要： coroutine: stackless和stackful jmp 基于switch的trick: http://www.chiark.greenend.org.uk/~sgtatham/coroutines.html 文中提到高德纳另有一套办法. #define crBegin static int state=0; switch(state) { case 0:#define crReturn(x) do { state=__LINE__; return x; \ case __LINE__:; } while (0)#defin... 阅读全文