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if (openFileDialog1.ShowDialog() == DialogResult.OK) { Filename = openFileDialog1.FileName; string strCon =... 阅读全文
posted @ 2014-06-13 13:04
BarneyX
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摘要:
1 using System; 2 using System.Data; 3 using System.Data.OleDb; 4 5 namespace AccessDb 6 { 7 /**//// 8 /// Acc... 阅读全文
posted @ 2014-06-13 13:02
BarneyX
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