摘要: int n1=10; int n2=20; n1=n1-10;//n1=-10,n2=20; n2=n1+n2;//n1=-10,n2=10; n1=n2-n1//n1=20;n2=10 阅读全文
posted @ 2020-02-07 17:10 fillt 阅读(166) 评论(0) 推荐(0) 编辑