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摘要: pa 2018-1-14 谷歌家面的是product analyst,一开始说是general hire,但好像面的时候直接见到了hardware team的一个年轻hiring manager,所以应该就是直接面那个组了。一开始一轮电面,是个youtube的老印面的,主要是问简历,让挑一个觉得最满 阅读全文
posted @ 2018-11-20 07:37 ffeng0312 阅读(1339) 评论(0) 推荐(0)
摘要: 2016-10-181. Coding: very simple, like tree pre-order traversal 2. search a number in ordered array without knowing the array length 3. leetcode 53 4. 阅读全文
posted @ 2018-11-10 05:25 ffeng0312 阅读(257) 评论(0) 推荐(0)
摘要: 2015-3-11 phone under hr,coding is not required 1. Describe a project that you are post proud of.2. Which statistical method do you think is most over 阅读全文
posted @ 2018-11-10 05:23 ffeng0312 阅读(2036) 评论(0) 推荐(0)
摘要: onsite5轮+Discussion with HR 由于很人很多,我已经忘记了每个interview的国籍啥的,全是男的,一个印度人,一个亲切的中国人,三个白人。大部分都是behavior question 和project experience, 我没有被直接问到任何tech问题但是在proj 阅读全文
posted @ 2018-11-10 05:21 ffeng0312 阅读(2044) 评论(0) 推荐(0)
摘要: https://www.researchgate.net/post/How_can_I_study_the_past_spending_behaviour_of_a_customer_in_a_banking_perspective_and_predict_the_next_purchase_cat 阅读全文
posted @ 2018-11-10 05:12 ffeng0312 阅读(843) 评论(0) 推荐(0)
摘要: select d.name Department, e.name Employee, e.salary Salary from Employee einner join Department d on e.DepartmentId = d.idwhere (e.DepartmentId,e.sala 阅读全文
posted @ 2018-10-28 10:13 ffeng0312 阅读(168) 评论(0) 推荐(0)
摘要: select s1.score Score, count(*) Rank from Scores s1,(select distinct score from scores) s2where s1.score <= s2.scoregroup by id,s1.scoreorder by count 阅读全文
posted @ 2018-10-24 20:19 ffeng0312 阅读(141) 评论(0) 推荐(0)
摘要: CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INTBEGINdeclare M int;set M = N-1;RETURN ( # Write your MySQL query statement below. select distinc 阅读全文
posted @ 2018-10-24 20:02 ffeng0312 阅读(161) 评论(0) 推荐(0)
摘要: https://leetcode.com/problems/second-highest-salary/solution/two row has the same salary, should return null, so we use distinct salarySELECT IFNULL( 阅读全文
posted @ 2018-10-23 20:11 ffeng0312 阅读(95) 评论(0) 推荐(0)
摘要: https://leetcode.com/articles/biggest-single-number/ select max(num) from (SELECT num FROM numbergroup by numhaving count(*)=1) n 阅读全文
posted @ 2018-10-23 19:58 ffeng0312 阅读(153) 评论(0) 推荐(0)
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