摘要: 方法一 SELECT user_id,sumAmount,max(op_time) from test GROUP BY user_id 方法二 SELECT * from (SELECT * from test ORDER BY op_time) b GROUP BY user_id 阅读全文
posted @ 2021-03-04 17:20 不愿意透露姓名的华 阅读(128) 评论(0) 推荐(0)