feng_linxu

对节点进行操作（1）hdu 1166 敌兵布阵这是简单的练手题View Code #include <stdio.h>#include <stdlib.h>#include <string.h>#define size 50010int sum[size<<2];void PushUp(int rt){ int ls,rs; ls=rt<<1;rs=rt<<1|1; sum[rt]=sum[ls]+sum[rs];}void build_tree(int l,int r,int rt){ int m=(l+r)>&g Read More