摘要: 1、验证二叉搜索树 关键:递归,设置区间,当前节点是左子树的上界,右子树的下界 class Solution: def isValidBST(self, root: Optional[TreeNode]) -> bool: return self.pd(root,-999999999999,9999 阅读全文
posted @ 2022-07-22 16:34 肥余 阅读(32) 评论(0) 推荐(0)