摘要:
clc; clear; wq = []; for i = 2:10000 sum = 0; k = 1; for j = 2: i / 2 if mod(i,j) == 0 sum = sum + j; end end if sum + 1 == i wq=[wq i]; en... 阅读全文
posted @ 2017-08-01 09:52
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摘要:
输入数字,0结束,判断输入的数字中的素数 阅读全文
posted @ 2017-08-01 09:51
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