poj 3308 Paratroopers

http://poj.org/problem?id=3308

 1 #include <cstdio>
 2 #include <cstring>
 3 #include <algorithm>
 4 #include <queue>
 5 #include <cmath>
 6 #define maxn 10000
 7 using namespace std;
 8 
 9 const int inf=1<<30;
10 int n,m,l,x,y;
11 double c,f;
12 double cap[200][200],flow[200][200];
13 int p[200];
14 double a[200];
15 
16 void EK(int s)
17 {
18    queue<int>q;
19    memset(flow,0,sizeof(flow));
20    f=0;
21    for(; ;)
22    {
23        memset(a,0,sizeof(a));
24        memset(p,-1,sizeof(p));
25        a[s]=inf;
26        q.push(s);
27        while(!q.empty())
28        {
29            int u=q.front();
30            q.pop();
31            for(int v=0; v<=m+n+1; v++)
32            {
33                if(!a[v]&&cap[u][v]>flow[u][v])
34                {
35                    p[v]=u;
36                    q.push(v);
37                    a[v]=min(a[u],cap[u][v]-flow[u][v]);
38                }
39            }
40        }
41        if(a[m+n+1]==0) break;
42        for(int u=m+n+1; u!=0; u=p[u])
43        {
44            flow[p[u]][u]+=a[m+n+1];
45            flow[u][p[u]]-=a[m+n+1];
46        }
47        f+=a[m+n+1];
48    }
49 }
50 
51 int main()
52 {
53     int T;
54     scanf("%d",&T);
55     while(T--)
56     {
57         memset(cap,0,sizeof(cap));
58         scanf("%d%d%d",&m,&n,&l);
59         for(int i=1;i<=m; i++)
60         {
61             scanf("%lf",&c);
62             cap[0][i]=log(c);
63         }
64         for(int i=m+1; i<=m+n; i++)
65         {
66             scanf("%lf",&c);
67             cap[i][m+n+1]=log(c);
68         }
69         for(int i=0; i<l; i++)
70         {
71             scanf("%d%d",&x,&y);
72             cap[x][m+y]=inf;
73         }
74         f=0;
75         EK(0);
76         printf("%.4f\n",exp(f));
77     }
78     return 0;
79 }
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posted @ 2014-02-18 14:32  null1019  阅读(144)  评论(0编辑  收藏  举报