摘要: select s.*from ( select row_number() over (partition by [分组字段] order by [排序字段] desc) as order_num,v.* from [表名] v) swhere s.order_num = 1 阅读全文
posted @ 2024-07-15 15:22 f_mao 阅读(159) 评论(0) 推荐(0)