摘要: SELECT 字段1, [列名] = stuff(( SELECT ',' + [字段2] FROM aa t WHERE t.字段1 = aa.字段1 FOR xml path('')) , 1 , 1 , '') FROM aaGROUP BY 字段1 阅读全文
posted @ 2023-10-25 10:36 f_mao 阅读(401) 评论(0) 推荐(0)