摘要: 2.有序字典: dic = collections.OrderedDict() dic['K1'] = 'V1'dic['K2'] = 'V2'dic['K3'] = 'V3'dic['K4'] = 'V4' dic.update({'K1':'V232', 'K5':'V5'}) #数据存在的话就 阅读全文
posted @ 2016-04-11 14:59 张瑞东 阅读(294) 评论(0) 推荐(0)