EricYang

摘要： Gone FishingTime Limit:2000MSMemory Limit:32768KTotal Submissions:24255Accepted:7082DescriptionJohn is going on a fishing trip. He has h hours available (1 <= h <= 16), and there are n lakes in the area (2 <= n <= 25) all reachable along a single, one-way road. John starts at lake 1, but 阅读全文

摘要： Max SequenceTime Limit:3000MSMemory Limit:65536KTotal Submissions:13533Accepted:5654DescriptionGive you N integers a1, a2 ... aN (|ai| <=1000, 1 <= i <= N).You should output S.InputThe input will consist of several test cases. For each test case, one integer N (2 <= N <= 100000) is gi 阅读全文

摘要： Maximum sumTime Limit:1000MSMemory Limit:65536KTotal Submissions:27486Accepted:8410DescriptionGiven a set of n integers: A={a1, a2,..., an}, we define a function d(A) as below:Your task is to calculate d(A).InputThe input consists of T(<=30) test cases. The number of test cases (T) is given in th 阅读全文

摘要： Subway tree systemsTime Limit:1000MSMemory Limit:10000KTotal Submissions:5735Accepted:2370DescriptionSome major cities have subway systems in the form of a tree, i.e. between any pair of stations, there is one and only one way of going by subway. Moreover, most of these cities have a unique central 阅读全文

摘要： Jury CompromiseTime Limit:1000MSMemory Limit:65536KTotal Submissions:21248Accepted:5424Special JudgeDescriptionIn Frobnia, a far-away country, the verdicts in court trials are determined by a jury consisting of members of the general public. Every time a trial is set to begin, a jury has to be selec 阅读全文

摘要： 参见编程珠玑chap4 chap9，和编程之美3.3给定一个有序（不降序）数组arr,，求任意一个i使得arr[i]等于t，不存在返回-1不变式：x[low]< =t<=x[high]int biSearch(int *arr, int low, int high, int t){ int mid; while(low<=high) { mid=low+(high-low)/2; if(arr[mid]==t) { return mid; } else if(arr[mid]>t) ... 阅读全文

摘要： 1 //µÝ¹éºÍ·ÇµÝ¹é±éÀúTree 2 // 1 3 // / \ 4 // 2 3 5 // / \ / \ 6 // 4 5 6 7 7 //Pre-Order: 1 2 4 5 3 6 7 8 //In-Order: 4 2 5 1 6 3 7 9 //Post-Order:4 5 2 6 7 3 1 10 11 #include <iostream> 12 #include <cstdio> 阅读全文

摘要： zzhttp://blog.csdn.net/dlengong/article/details/7408019输入括号的数目，输出括号的各种合法匹配样式 如输入 2输出( （））（）（）据说这是一道某公司的面试题，我们先来分析一下。括号匹配有合法有的不合法 如 （（）））（ 这样就不是合法的匹配样式。为了避免这种情况的出现，记录当前左括号的个数和右括号的个数，使右括号的个数不大于左括号的个数。主要思想类似于0-1背包问题，当进行到某一步的时候 有两种方法：放'（' 和 放 '）' 1 #include <iostream> 2 #include &l 阅读全文

摘要： 字符串比较函数，这个函数也比较常用：view plaincopy to clipboardprint?int strcmp(const char* str1,const char* str2){ assert(str1!=NULL&&str2!=NULL); while(*str1&&*str2&&*str1==*str2){ str1++; str2++; } if(*str1==*str2&&*str1==0) return 0;//equal else if(*str1... 阅读全文

摘要： Brackets SequenceTime Limit:1000MSMemory Limit:65536KTotal Submissions:19727Accepted:5465Special JudgeDescriptionLet us define a regular brackets sequence in the following way:1. Empty sequence is a regular sequence.2. If S is a regular sequence, then (S) and [S] are both regular sequences.3. If A a 阅读全文