摘要：
1 写出一个函数，取到链表中倒数第二个节点。双链表：node* getSec(List mylist){ return mylist.m_tail->m_prev; //m_prev为链表前指针}单链表：node* getSec(List mylist){ node* rsec = mylist.m_head; node* rfirst = rsec->m_next; for(;rfirst != mylist.m_tail ; rsec = rsec->m_next) { rfirst = rsec->m_next;}return rsec;}2 找出数组中第二大的数 阅读全文
posted @ 2012-11-04 10:54
emmac
阅读(485)
评论(0)
推荐(0)
浙公网安备 33010602011771号