摘要: sql语句 select a.house_no as '房子',substring_index(substring_index(a.name,',',b.help_topic_id+1),',',-1) as '拥有者' from aa ajoin mysql.help_topic b on b.h 阅读全文
posted @ 2019-02-15 11:30 zhangkui 阅读(6926) 评论(0) 推荐(0)