作业1

实验一

#include<stdio.h>
int main() {
    printf(" o \n");
    printf("<H>\n");
    printf("I I\n");    
for (int i = 0; i < 2; i++) {
        printf(" o \n");
        printf("<H>\n");
        printf("I I\n");
    }
    printf(" o    o \n");
    printf("<H>  <H>\n");
    printf("I I  I I\n");
    return 0;
}

 

实验二
#include<stdio.h>
int main() {
    double a, b, c;
    scanf_s("%lf%lf%lf",&a,&b,&c);
    if (a + b > c && b + c > a && a + c > b)
        printf("能构成三角形\n");
    else
        printf("不能构成三角形\n");
    return 0;
}

实验三

#include<stdio.h>
int main() {
    char ans1, ans2;
    printf("课前预习了吗？,课后复习了吗？(输入y表示是)\n");
        ans1 = getchar();
        getchar();
    printf("\n动手敲代码了吗?(输入y表示是)\n");
        ans2=getchar();
        if ((ans1== 'y' || ans1 == 'Y') && (ans2 == 'y' || ans2 == 'Y'))
            printf("\n罗马不是一天建成的, 继续保持哦");
        else
            printf("\n罗马不是一天毁灭的, 我们来建设吧");
        return 0;
}

实验四

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>

int main()
{
double x, y;
char c1, c2, c3;
int a1, a2, a3;

scanf("%d%d%d", &a1, &a2, &a3);

printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3);
scanf(" %c%c%c", &c1, &c2, &c3);

printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
scanf("%lf%lf", &x, &y);

printf("x = %f, y = %lf\n", x, y);
return 0;
}

实验5

#include<stdio.h>
int main() {
    int year;
    year =1000000000 / 60 / 60 / 24/365+0.5;
    printf("十亿秒等于%d年\n",year);
    return 0;
}

#include<stdio.h>
#include<math.h>
int main() {
    double x, ans;

    while (scanf_s("%lf", &x) != EOF)
    {
        ans = pow(x, 365);
        printf("%.2f的365次方：%.2f\n", x, ans);
        printf("\n");
    }
    return 0;
}

#include<stdio.h>
int main() {
    double F, c;
    while (printf("\n输入摄氏度\n"),scanf_s("%lf", &c) != EOF) {
        F = 9.0 / 5.0 * c + 32;
        printf("华氏度%lf\n", F);
    }
    return 0;
}

#include<stdio.h>
#include<math.h>
int main() {
    printf("计算三角形面积\n");
    double a, b, c, s, ans;
    while (printf("\n请输入三角形三边长度\n"),scanf_s("%lf%lf%lf", &a, &b, &c)!=EOF) {
        if (a + b > c&& b + c > a&& a + c > b) {
            s = (a + b + c) / 2;
            ans = pow(s * (s - a) * (s - b) * (s - c), 0.5);
            printf("三角形面积为%.3f\n", ans);
        }
        else {
            printf("这不是三角形\n");
        }
    }
    return 0;
}