摘要:
View Code #include<stdio.h>#include<string.h>#include<stdlib.h>struct node{ long long x,y;}p[50003],a[50003],t1;long long mul(node p1,node p2,node p3){ return (p2.x-p1.x)*(p3.y-p1.y)-(p2.y-p1.y)*(p3.x-p1.x);}long long dis(node a,node b){ return (a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b. 阅读全文
posted @ 2012-05-20 21:25
'wind
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