摘要:
Reverse a singly linked list.思路:没啥好说的。秒...ListNode* reverseList(ListNode* head) { ListNode * rList = NULL, * tmp = NULL; while(head != N... 阅读全文
posted @ 2015-05-21 10:38
匡子语
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摘要:
Given two stringssandt, determine if they are isomorphic.Two strings are isomorphic if the characters inscan be replaced to gett.All occurrences of a ... 阅读全文
posted @ 2015-05-21 10:26
匡子语
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摘要:
Count the number of prime numbers less than a non-negative number,n思路:数质数的个数开始写了个蛮力的,存储已有质数,判断新数字是否可以整除已有质数。然后妥妥的超时了(⊙v⊙)。看提示,发现有个Eratosthenes算法找质数的,说... 阅读全文
posted @ 2015-05-21 10:13
匡子语
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