用jquery把一个List里面的对象的属性，依次填入到一个table里面啊
假设list格式如下list = [{"id":"1","name":"A","age":20}, {"id":"2","name":"B","age":21},{"id":"3","name":"C","age":22}];
最简单的就 是
for(var index = 0,l = list.length;index<l;index++)
{ $("#students tbody").append("<tr><td>"+ list[index].id +"</td><td>"+ list[index].name+"< /td><td>"+ list[index].age +"</td>< /tr>"); }
students 是table的id
<!DOCTYPE html PUBLIC "-//W3C //DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD /xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999 /xhtml"><head>
<meta http-equiv="Content-Type" content="text /html; charset=gb2312" />
<title>无标题文档</title>
</head>
<script language="javascript" src="/js/jquery-1.4.4.js" type="text /javascript">< /script>
<script language="javascript" type="text/javascript">
$(document).ready(function () {
var list = [{"id":"1","name":"A","age":20}, {"id":"2","name":"B","age":21}, {"id":"3","name":"C","age":22}];
for(var index = 0,l = list.length; index<l;index++) {
$("#students tbody").append("<tr><td>"+ list[index].id +"</td><td>"+ list[index].name+"< /td><td>"+ list[index].age +"</td>< /tr>");
} })
</script>
<body>
<table id="students">
<thead> <tr> <th>学 号</th> <th>姓名</th> <th>年龄< /th> </tr> </thead>
<tbody>
</tbody>
</table>
</body>
