题意:从圆上一点发出射线经过n次反射回到起点,求方案数;思路:发射射线与其在该点相切的线的夹角记作sita,则每条边所对应的圆心角为2*sita,反射n次有n+1条边,则2*sita*(n+1)=2*k*pi,k为整数; sita=pi*k/(n+1);sita的种类数与k与(n+1)互质的情... Read More
posted @ 2015-09-05 23:12 dominating大树置林 Views(203) Comments(0) Diggs(0)