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Given isSubstring() which checks if one word is a substring of another, write code to check if s2 is a rotation of s1. class Solution { public bool... 阅读全文
posted @ 2015-02-17 06:37
江南第一少
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class Solution { public String compress(String str) { int size = countCompression(str); //先check compress之后的size,若更大,返回原string。 if(size >= str.leng... 阅读全文
posted @ 2015-02-17 06:26
江南第一少
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Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(x) -- Push element x onto stack.pop() -- Removes... 阅读全文
posted @ 2015-02-17 00:22
江南第一少
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