摘要: #获取周一,周二..... lexin_df['weekday'] = lexin_df['approve_date'].map(lambda x:x.weekday()+1) #获取小时 lexin_df['hour'] = lexin_df['approve_date'].map(lambda 阅读全文
posted @ 2022-03-25 11:42 地豆苗 阅读(782) 评论(0) 推荐(0)