摘要: 牛客 周赛94 20250531 https://ac.nowcoder.com/acm/contest/110696 A: 题目大意: void solve(){ int n; cin>>n; cout<<(n+1)/2<<endl; } 签到 B: 题目大意: int a[4],b[4],n; 阅读全文
posted @ 2025-05-31 15:31 才瓯 阅读(20) 评论(0) 推荐(0)